$B_{8A}$
$${\rm LOG}\left(B_{8A}\right)=\frac{1}{10}\pi
\left[\begin{array}{rrrrrrrr}
\bullet& \bullet& \bullet& \bullet& \bullet& \bullet& \bullet& \bullet\\
\bullet& 5& 10& 13& 8& 3& 15& 18\\
\bullet& 10& 5& 18& 3& 13& 15& 8\\
\bullet& 12& 7& 10& 15& 17& 5& 2\\
\bullet& 17& 2& 15& 10& 7& 5& 12\\
\bullet& 7& 17& 3& 13& \bullet& 10& 10\\
\bullet& 2& 12& 8& 18& 10& \bullet& 10\\
\bullet& 15& 15& 5& 5& 10& 10& \bullet
\end{array}\right]$$